The shown ideal op-amp has infinite gain and bandwidth and ±10 V supplies. Inputs 0.1 V and 1 V connect via 1 kΩ to the inverting and non-inverting terminals respectively. Feedback resistors are 2 kΩ to the inverting node and 5 kΩ to the non-inverting node. Find Vₒ in V to one decimal.
Negative feedback dominates and the output remains within the rails, so both input nodes equal v. KCL at the inverting node gives (v−.1)/1+(v−Vo)/2=0, hence Vo=3v−.2. At the non-inverting node, (v−1)/1+(v−Vo)/5=0, so Vo=6v−5. Equating gives v=1.6 V and Vo=4.6 V.
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