GATE 2016 EE (EE2) – Question 57

Power Electronics · DC to DC conversion: Buck, Boost and Buck-Boost Converters · 2 marks · Numerical answer

An ideal boost converter increases 360 V to 400 V at 4 kW with continuous inductor current. Find rms switch current in amperes.

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Correct answer: 3.0 to 4.0

Explanation

The duty ratio is D=1−Vin/Vout=0.1. Average input/inductor current is P/Vin=4000/360=11.1111 A.

With the small-ripple approximation used by the key, the switch carries that current during fraction D and zero otherwise. Thus Is,rms≈IL√D=**3.51364 A**, within 3–4 A.

An exact finite-ripple rms calculation needs switching frequency, which the source does not specify; continuous current alone does not determine that correction.

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