A peptide is Phe–Leu–Ile–Met–Ser–Leu. Use the supplied codon counts: Phe 2, Leu 6, Ile 3, Met 1, Ser 4. How many unique DNA sequences can encode the peptide?
Multiply independent codon choices at each of the six positions, including both leucines: $2\times6\times3\times1\times4\times6=864$. The supplied count of four serine codons is used as instructed; the full standard genetic code has six serine codons, so substituting that biological count would answer a different numerical problem.
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