Mining Methods and Machinery · Mining Methods · 2 marks · Numerical answer
A surface miner has drum width 3 m, cutting depth 20 cm, cutting speed 25 m/min and pit length 500 m. Turning takes 2 min. Truck exchange takes 30 s and each truck holds 15 m³. Find in-situ production in m³/hour, to one decimal.
One pass cuts 3×0.20×500=300 m³ in 500/25=20 min. It fills 300/15=20 truckloads, with exchange allowance 20×0.5=10 min. Including a 2 min turn, cycle time is 32 min. Output is 300/32×60 = 562.5 m³/hour. Use in-situ volume throughout, as requested.
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