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GATE 2014 EC (EC2) – Question 51

Digital Circuits · Sequential Circuits · 2 marks · Multiple choice

Both flip-flop outputs Q₁,Q₂ start at 0. Find the sequence generated at Q₁ by the clock.

Diagram for GATE 2014 EC (EC2) question 51
  1. 01110…
  2. 01010…
  3. 00110…
  4. 01100…

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Show answer and explanation

Correct answer: (D) 01100…

Explanation

The connections give J1=Q̄2,K1=Q2 and J2=Q1,K2=Q̄1, so the next-state equations are Q1+=Q̄2 and Q2+=Q1. Starting at(Q1,Q2)=00, the states are00→10→11→01→00. Including the initial bit, Q1 therefore reads **01100…,D**, repeating as a4state Johnson counter.