Methoxide is a strong base and the substrate is secondary, so E2 elimination dominates. Rotate the C2–C3 bond to place C–Br antiperiplanar to the β-C–H bond; removal gives the more substituted C2=C3 alkene. The specified R,R stereochemistry then places the higher-priority carbon groups on opposite sides. The major product is **(E)-3-methylpent-2-ene, B**.