GATE 2024 EC – Question 41
The propagation delay of the $2\times1$ MUX shown in the circuit is 10 ns. Consider the propagation delay of the inverter as 0 ns.
If $S$ is set to 1 then the output $Y$ is ______.

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Correct answer: (B) a square wave of frequency 50 MHz
Explanation
With $S=1$ the MUX passes input 1, which is $\overline Y$ (the inverted output, with no inverter delay). So $Y$ becomes $\overline Y$ after 10 ns: the output toggles every 10 ns. The period is 20 ns, i.e. a 50 MHz square wave.